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7v^2-3v-7=0
a = 7; b = -3; c = -7;
Δ = b2-4ac
Δ = -32-4·7·(-7)
Δ = 205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{205}}{2*7}=\frac{3-\sqrt{205}}{14} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{205}}{2*7}=\frac{3+\sqrt{205}}{14} $
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